A non conducting ring of radius R has uniformly distributed positive charge. A small part of the ring, of length d, is removed (d << R). The electric field at the centre of the ring will now be –
Text Solution
Verified by ExpertsThe correct answer is:
A
Let Q = charge on entire ring.
Charge on section removed
For the complete ring, field at C is zero. Let E 1 and E 2 be the fields at the centre due to dQ and due to the remaining ring respectively.
and E 2 must be equal and opposite.
E 2 is directed towards gap 
.
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