Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Five identical capacitor plates each of area A are arranged such that adjacent plates are at a distance d apart. The plates are connected to a source of emf V as shown in figure The charge on plate 1 is .................. and that on plate 4 is ..................
Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: Understand that the arrangement of plates is a series of capacitors. Each adjacent pair of plates forms a capacitor.
Step 2: The total voltage V is distributed across the capacitors. Since the plates are identical and the distances between them are equal, the charge on each plate will differ based on its position in the series connection.
Step 3: For plate 1, the total charge will be equal to the voltage multiplied by capacitance: Q_1 = C * V.
Step 4: For plate 4, the charge will also depend on the distribution in a series arrangement. The charge generally decreases toward the last plate.
Therefore, the charge on plate 1 is greater as compared to plate 4.
Step 2: The total voltage V is distributed across the capacitors. Since the plates are identical and the distances between them are equal, the charge on each plate will differ based on its position in the series connection.
Step 3: For plate 1, the total charge will be equal to the voltage multiplied by capacitance: Q_1 = C * V.
Step 4: For plate 4, the charge will also depend on the distribution in a series arrangement. The charge generally decreases toward the last plate.
Therefore, the charge on plate 1 is greater as compared to plate 4.
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