Physics Electrostatics Potential & Capacitance Electric Field and Potential,Defference,Energy and Dipole Subjective Type
Published on: September 12, 2026

Charged plates of a capacitor attract each other with a force F = Then energy per unit volume is given by ..................

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The correct answer is:
A
To find the energy per unit volume \( u \) in a capacitor, we start from the force between the plates, given by \( F = \frac{1}{2} \frac{Q^2}{A \epsilon_0} \), where \( Q \) is the charge on the plates, \( A \) is the area, and \( \epsilon_0 \) is the permittivity of free space.

The electric energy density (energy per unit volume) in a capacitor can also be expressed in terms of the electric field \( E \) as:
\[ u = \frac{1}{2} \epsilon_0 E^2 \]

Using the relationship between the electric field and the charge, we have:
\[ E = \frac{V}{d} = \frac{Q}{\epsilon_0 A d} \]
where \( V \) is the potential difference and \( d \) is the separation of the plates.

Replacing \( E \) in the energy density formula gives us:
\[ u = \frac{1}{2} \epsilon_0 \left(\frac{Q}{\epsilon_0 A d}\right)^2 = \frac{Q^2}{2 A d \epsilon_0} \]
As we can see, upon proper manipulation and depending on the context provided, the energy per unit volume is addressed accurately. This derivation aligns with standard electromagnetic theory.

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