A positive charge of q 1 is located 3.00 m to the left of a negative charge –q 2 . Magnitude of charge q 1 greater than magnitude of negative charge q 2 . The net electric field intensity is zero at a point on the line passing through charges. On this line there are also points where the potential is zero. Locate these two points relative to the negative charge –
A
At 0.2 m left of negative charge
B
At 0.2 m right of negative charge
C
At 
m left of negative charge
m left of negative charge
D
At 
m right of negative charge
m right of negative charge
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(b, c)
q 1 = 16q 2 ...(i)
V at P = 0
3 + x = 16x
3 = 15x
x = 15x
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The law, governing the force between electric charges is known as
When the distance between the charged particles is halved, the force between them becomes
There are two charges +1 microcoulombs and +5 microcoulombs. The ratio of the forces acting on them…
A charge q 1 exerts some force on a second charge q 2 . If third charge q 3 is brought near, the fo…
and represents gravitational and electrostatic force respectively between electrons situated at a…
The ratio of the forces between two small spheres with constant charge in air in a medium of diel…