The internal resistance of the cell shown in the figure is …

Physics Current Electricity Kirchhoff's Law, EMF of The Cells, Internal Resistance MCQ (Single Correct)

The internal resistance of the cell shown in the figure is negligible. On closing the key K, the ammeter reading changes from 0.25 amp to amp, then –

R 1 = 10 Ω Ω

R 1 = 15 Ω Ω

Power drawn from the cell increases

The current through R decreases by 40%

Text Solution

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The correct answer is:

CHECK THE SOLUTION.

(b, c)

When K was open

Reading of = amp = 0.25

∴ E = 2.5 V

When K was closed

Reading of = =

12 (5 + 0.5 R 1 ) = 10R 1

60 + 6R 1 = 10R 1

R 1 = 15 Ω Ω

Power drawn =

As R eq decreases

Power = will increases

current through R = 0.25 amp (initially)

After K is closed current through R = 0.25 amp

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