A 4 kg particle is moving along the x-axis under the action of the force F = - 
x N. When t = 2s, the particle passes through the origin and when t = 10s, its speed is 4√2 m/s. The amplitude of the motion is:
A
m/s
B
m/s
C
m/s
D
m/s
Text Solution
Verified by ExpertsThe correct answer is:
A
a = - 
x
⇒ ⇒ ω ω = 
T = 
=16 sec.
There is a time difference of 
between t = 2 sec. to
t = 10 sec. Hence particle is again passing through mean
position of SHM where its speed is maximum.
i.e. V max = A ω ω = 4 √ √ 2
A = 
= 
m/s.
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