In a cylindrical water tank there are two small holes Q and P on the wall at a depth of h 1 form upper level of water and at a height of h 2 from the lower end of the tank respectively as shown in the figure. Water coming out from both the holes strike the ground at the same point. The ratio of h 1 and h 2 is:
Text Solution
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The two streams strike at the same point on the ground,
⇒ ⇒ R 1 = R 2 = R
⇒ ⇒ v 1 t 1 = v 2 t 2 …(1)
where v 1 = velocity of efflux at 1 = 
and v 2 = velocity
of the efflux at 2
= 
t 1 = Time of fall of the water stream through
(1) = 
t 2 = Time of fall of the water stream through (2) = 
Putting these values in equation (1), we obtain,
(H – h 1 ) h 1 = (H – h 2 ) h 2 ⇒ ⇒ [H-(h 1 + h 2 )] [h 1 – h 2 ] = 0
⇒ ⇒ H = h 1 + h 2 is irrelevant because the holes are at two
different heights, therefore h 1 = h 2 ⇒ ⇒ (h 1 /h 2 ) = 1
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