The figure shows a model of perfume atomizer. When the bulb A is compressed, air flows through the narrow tube. Consequently, pressure at the position of the vertical tube reduces. The liquid (perfume) rises through the vertical tube and emerges through the end. If the excess pressure applied to the bulb in this process be Δ Δ p, the minimum speed of air in the tube to lift the perfume is:
Text Solution
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Applying Bernoulli’s principle at 1 and 2, we obtain
P 1 + 1/2 ρ ρ a 
= P 2 + 1/2 p 
putting, v 1 = 0 since the air is at rest inside the bulb,
P 1 = P 0 + Δ Δ p, P 2 = P 0 – ρ ρ gh
where ρ ρ = density of liquid (perfume)
ρ ρ a = density of air v 2 = minimum velocity of air to lift the
liquid through the height h = v (say)
p 0 = atmospheric pressure
We obtain,
v = 
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