A pipe ABCD of uniform cross-section is bent into three sections, viz., a horizontal section AB, a vertical section BC with C below B, and a horizontal section CD. Liquid flowing through the pipe has speed v 1 and pressure p 1 in section AB, and speed v 2 and pressure p 2 in section CD -
Text Solution
Verified by ExpertsThe correct answer is:
B
v 1 = v 2 (equation of continuity)
Also; 
+ gh + 
= 
+ 0 + 
P 2 – P 1 = h ρ g ∴ P 2 > P 1
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