A carnot engine works between ice point and steam point. It is desired to increase efficiency by 20%, by changing temperature of sink to –
Text Solution
Verified by ExpertsThe correct answer is:
A
Temp. of source T 1 = 100 + 273 = 373 K.
Temp of sink T 2 = 0 + 273 = 273 K.
Efficiency of carnot engine
η = 1 – 
= 1 – 
η = 
To increase η′ = 
+ 
× 
= 
η′ = 1 – 
= 
or T 2 = 
× 373 = 253 K.
New sink temp = 253K
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