An ideal gas at (P, V, T) is expanding adiabatically to 5.66 times the volume and half the temperature. The degree of freedom f of the gas and work done W by the gas –
A
W = 0, f = 5
B
W = PV, f = 7
C
W = 
P, f = 7
P, f = 7
D
W = 
PV, f = 5
PV, f = 5
Text Solution
Verified by ExpertsThe correct answer is:
D
For an adiabatic process
T 1 
= T 2 
Given T 2 = 
and
V 2 = 5.66 V 1
= 
2 = (5.66) γ-1 Or γ = 1.458
Hence gas is diatomic having f = 5.
W = 
and 
= 
= 
P 2 = 
and
V 2 = 5.66 V 1
= 
= 
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