Figure shows the variation of internal energy 'U' with the density of one mole of monoatomic gas for a thermodynamic cycle ABCA. AB process is a rectangular hyperbola. The amount of work done in the process A → B is:
A
B
– 
C
D
– 
Text Solution
Verified by ExpertsThe correct answer is:
D
For the process A → B
U α 
⇒ 
RT α 
or T α V
So AB is isobaric process (Pressure is constant)
T A = 
[As 4U 0 = 3/2 RT A ]
V A = 
So, p A = 
& V B = 
So W AB = p[v B – v A ]
⇒ 
= – 
× 
⇒ – 
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