A block of mass m is on inclined plane of angle θ. The coefficient of friction between the block and the plane is µ and tan θ > µ. The block is held stationary by applying a force P parallel to the plane. The direction of force pointing up the plane is taken to be positive. As P is varied from P 1 = mg (sin θ – µcos θ) to P 2 = mg (sin θ + 
cos θ), the frictional force f versus P graph will look like:
Text Solution
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P1 = mg sin θ – µmg cos θ
P2 = mg sin θ + µmg cos θ
Initially block has tendency to slide down and as tan θ > µ, maximum friction µmg cos θ will act in
positive direction. When magnitude P is increased from P 1 to P 2 , friction reverse its direction from
positive to negative and becomes maximum i.e. µmg cos θ in opposite direction.
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