Two identical prisms with slightly different indices are located as shown. Angle θ is small. When a laser beam strike one of the prisms perpendicular to the surface, the refracted ray is deviated by a small angle φ . Find the difference between the indices of refraction of the prism in term of θ & φ -
Text Solution
Verified by ExpertsThe correct answer is:
B

n 1 sin θ = n 2 sinr
n 1 θ = n 2 r for small angles
we can apply Snell's law at the exit vertical plane of the second prism.
n 2 sin (r – θ ) = sin φ
n 2 r – n 2 θ = φ
n 1 θ = n 2 r
– n 2 θ = φ]
n 1 – n 2 = 

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