A

Step 1: Use the magnification formula for mirrors:
Magnification (M) = \frac{height_{image}}{height_{object}} = -\frac{image\ distance (v)}{object\ distance (u)}
Given that the image is 2 times magnified and real, we have M = -2. Thus, we can write:
-2 = -\frac{v}{u} This simplifies to:
v = 2u

Step 2: Use the mirror formula:
\frac{1}{f} = \frac{1}{u} + \frac{1}{v}
Here, f = -10 cm (focal length is negative for concave mirrors). We can substitute v with 2u into the mirror formula:
\frac{1}{-10} = \frac{1}{u} + \frac{1}{2u}
Step 3: Finding a common denominator:
\frac{1}{-10} = \frac{2 + 1}{2u} = \frac{3}{2u}
Step 4: Cross-multiplying gives us:
3 \times -10 = 2u
-30 = 2u
u = -15 cm

Therefore, the distance between the object and the mirror is 15 cm (the negative sign indicates the object is in front of the mirror).