A ball of radius R = 20 cm has a mass m = 0.75 kg and moment of inertia about its diameter I = 0.0125 kg m 2 . The ball rolls without slipping over a rough horizontal floor with velocity v 0 = 10 m/s towards a smooth vertical wall. If coefficient of restitution between the wall and ball is e = 0.7 then the velocity of the ball in m/s after long time after collision is (g = 10 m/s 2 )
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Ans. 2
Sol. Let V 1 just after collision and V 2 after long time [ ω will not change]
e = 
⇒ V 1 = 0.7 × 10 = 7m/s
angular momentum conservation about O
mV 1 R – I ω 0 = mV 2 R + I 
V 2 = 2m/s
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