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CGP EDU Academic Team
Published on: September 12, 2026
The kinetic energy due to translational motion, of most of the molecules of an ideal gas at absolute temperature TK is ................
Text Solution
Verified by ExpertsThe correct answer is:
A
The average kinetic energy (KE) of the molecules of an ideal gas can be expressed using the formula:
$$ KE_{avg} = \frac{3}{2} k T $$
where k is the Boltzmann constant (1.38 x 10^-23 J/K) and T is the absolute temperature in Kelvin. For an ideal gas at absolute temperature TK, the average kinetic energy of the molecules is directly proportional to the temperature.
Therefore, the average kinetic energy due to translational motion of most molecules at absolute temperature TK is given by the formula above.
$$ KE_{avg} = \frac{3}{2} k T $$
where k is the Boltzmann constant (1.38 x 10^-23 J/K) and T is the absolute temperature in Kelvin. For an ideal gas at absolute temperature TK, the average kinetic energy of the molecules is directly proportional to the temperature.
Therefore, the average kinetic energy due to translational motion of most molecules at absolute temperature TK is given by the formula above.
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