Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A container of volume 1 m 3 is divided into two equal parts by a partition. One part has an ideal gas at 300 K and the other part is vacuum. The whole system is thermally isolated from the surroundings. When the partition is removed, the gas expands to occupy the whole volume. Its temperature will now be …….
Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: Identify the initial conditions of the system. We have a container of volume 1 m³, divided into two equal parts. One part contains an ideal gas at 300 K, while the other part is a vacuum, meaning it contains no gas.
Step 2: Understand the process after removing the partition. When the partition is removed, the ideal gas expands freely into the vacuum. This process is known as free expansion.
Step 3: Analyze the thermodynamic principles involved. Since the system is thermally isolated, there is no heat exchange with the surroundings (Q = 0). In addition, in a free expansion, no work is done on or by the gas (W = 0).
Step 4: Apply the first law of thermodynamics, which states: \( \Delta U = Q - W \). In this case, we have \( \Delta U = 0 - 0 = 0 \), implying that the internal energy of the gas remains unchanged.
Step 5: For an ideal gas, the internal energy is related to temperature. Since the internal energy remains constant, so does the temperature.
Step 6: Therefore, the final temperature of the gas after the partition is removed and it expands into the vacuum will remain at 300 K.
Therefore, the final answer is 300 K.
Step 2: Understand the process after removing the partition. When the partition is removed, the ideal gas expands freely into the vacuum. This process is known as free expansion.
Step 3: Analyze the thermodynamic principles involved. Since the system is thermally isolated, there is no heat exchange with the surroundings (Q = 0). In addition, in a free expansion, no work is done on or by the gas (W = 0).
Step 4: Apply the first law of thermodynamics, which states: \( \Delta U = Q - W \). In this case, we have \( \Delta U = 0 - 0 = 0 \), implying that the internal energy of the gas remains unchanged.
Step 5: For an ideal gas, the internal energy is related to temperature. Since the internal energy remains constant, so does the temperature.
Step 6: Therefore, the final temperature of the gas after the partition is removed and it expands into the vacuum will remain at 300 K.
Therefore, the final answer is 300 K.
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