Consider a car moving along a straight horizontal road with a speed of 72 km/h If the coefficient of static friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is (taking g=10m/s 2 )
Text Solution
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Step 1: Calculation of acceleration due to friction force
For stopping the car in shortest distance without skidding(sliding), the maximum static friction should act in opposite direction.

Now, Applying Newton's second law on car along x-direction (Rightwards Positive)

Negative means left direction (retardation)
Step 2: Calculation of Stopping distance
Since Retardation is constant, so applying kinematics equation of motion:




Shortest distance in which car can be stopped is 40 m
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