On moving a charge of 20 coulombs by 2 cm, 2 J of work is done, then the potential difference between the points is:
Text Solution
Verified by ExpertsThe correct answer is:
A
Potential difference between two points in a electric field is,
V A – V B = 
where, W is work done by moving charge q 0 from point A to B.
So V A – V B = 
(Here: W = 2 J, q 0 = 20C) = 0.1 V
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