The potential at a point x (measured in µm) due to some charges situated on the x-axis is given by V(x) = 20/(x 2 – 4) volts. The electric field E at x = 4 µm is given by:
Text Solution
Verified by ExpertsThe correct answer is:
D
v(x) = 
,
E = – 
= – 
= 
(2x)
E at x = 4 µm, 
= 
volt/µm
Also as x increases, V decreases. So, E is along +ve x -axis.
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