B

According to Gauss's Law, given by the equation
$$\varepsilon_0 \oint \vec{E} \cdot d\vec{s} = q_{enc}$$
where $q_{enc}$ is the net charge enclosed by the Gaussian surface. If the net charge enclosed by the Gaussian surface is zero (i.e., $q_{enc} = 0$), then the equation simplifies to:
$$\varepsilon_0 \oint \vec{E} \cdot d\vec{s} = 0$$
This indicates that the total electric flux through the Gaussian surface is zero. The total electric flux being zero implies that the number of electric field lines entering the surface is equal to the number of electric field lines exiting the surface.
Therefore, that leads us to conclude that the net incoming electric flux is zero, which corresponds to option B: Incoming and outgoing electric lines are equal.