An electric dipole is placed at an angle of 30º with an electric field intensity 2 ×10 5 N/C. It experiences a torque equal to 4 N m. The charge on the dipole, if the dipole length is 2cm, is
Text Solution
Verified by ExpertsThe correct answer is:
C
τ = PE sinθ
4 = P × 2 × 10 5 × 
⇒ P = 4 × 10 –5 cm = q × 2 × 10 –2
So, q = 
= 2×10 –3 coulomb
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Suppose the charge of a proton and an electron differ slightly One of them is -e the other is . I…
The diagrams below show regions of equipotential
A positive charge is moved from A to B in each di…
An electric dipole is placed at an angle of 30 with an electric field intensity It experiences a …
Two identical charged spheres suspended from a common point by two massless strings of lengths l, a…
If potential (in volts) in a region is expressed as , the electric field at point (1, 1, 0) is
A parallel plate air capacitor of capacitance C is connected to a cell of emf V and then disconnect…