Suppose the charge of a proton and an electron differ slightly. One of them is – e, the other is (e + Δ e). If the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance d (much greater than atomic size) apart is zero, then Δ e is of the order of [Given mass of hydrogen m h = 1.67 × 10 –27 kg
Text Solution
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Net Charge on one H-atom = –e + (e + Δ e) = Δ e
Net electrostatic force between two H-atoms
= 
repulsive
Net gravitational force between two H-atoms
= 
For equal magnitude
Δ e 2 = 
= 
Δ e 2 is of the order of 10 –74
Δ e is of the order of 10 –37
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