A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is:-
Text Solution
Verified by ExpertsThe correct answer is:
A
Maximum speed of a particle executing SHM is
u max = aꞷ = a(2 π n)
n = 
Here, u max = 31.4 cm/s, a = 5cm
Substituting, the given values, we have
n = 
= 1Hz
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