Match the column:
Column -I | Column -II |
(i) Binding Energy of electron in triply ionized Lithium atom | [A] 340 eV |
(ii) Energy that can remove electron from first excited state of tetra ionized Beryllium atom | [B] 3.4 eV |
(iii) Ionization energy of pentaionised Boron | [C] 122.4 eV |
(iv) Energy obtained in assembling singly ionized Helium atom so that the atom can be in ground state or other excited states | [D] 54.4 eV |
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
Ans.
(i) [C]
(ii) [D]
(iii) [A]
(iv) [B], [D]
Sol.
Ionization energy or Binding energy
E 0 = Z 2 . (13.6 eV)
Z = 3 for Lithium. E 0 = (3) 2 (13.6) = 9 × 13.6
E 0 = 122.4 eV
Energy of electron in any state in any atom is –
E = – 
× 13.6 eV
For Z = 4, n = 2; i.e., for Beryllium in first excited state E = – 
× 13.6 E = – 54.4 eV
Energy required is E req = – E = 54.4 eV
Ionization energy of pentaionised Boron is
E 0 = (Z) 2 × (13.6) = (5) 2 × 13.6
E 0 = 25 × 13.6 = 340 eV
When a system is assembled from its constituent’s energy is released (obtained)
For He + atom in ground state, E 1 = 
= 54.4 eV
For He + atom in third excited, E 2 = 
E 2 = 
= 3.4 eV
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