2 liter water at 27°C is heated by a 1 kW heater in an open container. On an average heat is lost to surroundings at the rate 160 J/s. The time required for the temperature to reach 77°C is
Text Solution
Verified by ExpertsThe correct answer is:
A
Net heat given/sec = 1000 – 160 = 840 J/S
if it takes a time t then
840 t = 2000 × 4.2 × (77 – 27)
t = 500 sec = 8 min 20 sec.
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