The system starts from rest and A attains a velocity of 5 m/s after it has moved 5 m towards right. Assuming the arrangement to be frictionless everywhere and pulley & strings to be light, if the constant force F applied on A then find the value of 
.
Text Solution
Verified by ExpertsThe correct answer is:
C
a = 
= 2.5 m/s 2
For 6 kg: – F – 2T = 6a
For 2 kg: – T – 2g = 2 (2 a)
From & F = 75 N
= 5.
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