A constant force F = m 1 g / 2 is applied on the block of mass m 2 as shown in figure. The string and the pulley are light and the surface of the table is smooth. Find the acceleration of m 2 .
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
It is obvious that acceleration of both the blocks is same in magnitude.
F – T = m 2 a [Newtons second law for m 2 ]
T – m1g = m 1 a [Newtons second law for m 1 ]
After adding the above equations.
F – m 1 g = (m 2 + m 1 ) a
– m 1 g = (m 2 + m 1 ) a
a = – 
The value of a is –ve it means
a = 
in the direction opposite to assumed direction
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