A

Step 1: Identify the key parameters of the problem:
Initial velocity (u) = 80 m/s
Angle of projection (θ) = 30°
Step 2: Determine the horizontal and vertical components of the initial velocity:
Horizontal component (u_x) = u * cos(θ) = 80 * cos(30°) = 80 * \frac{\sqrt{3}}{2} = 40\sqrt{3} \text{ m/s}
Vertical component (u_y) = u * sin(θ) = 80 * sin(30°) = 80 * \frac{1}{2} = 40 \text{ m/s}
Step 3: Calculate the time of flight (T):
The time of flight for a projectile is given by T = \frac{2u_y}{g}, where g is the acceleration due to gravity (approximately 9.81 m/s²).
T = \frac{2 * 40}{9.81} \approx 8.16 ext{ s}
Step 4: Calculate the range (R):
The range of the projectile is given by R = u_x * T
R = (40\sqrt{3}) * 8.16 = 40 * \sqrt{3} * 8.16 \approx 40 * 1.732 * 8.16 \approx 562 ext{ m}
Therefore, the range will be 562 m.