A body playing on the roof of a 10 m high building throws a ball with a speed of 10 m/s at an angle of 30º with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground? [g = 10 m/s 2 , sin 30º = 1/2, cos 30º = 
]
Text Solution
Verified by ExpertsThe correct answer is:
D
R = 
= 
= 10 × 
= 5 × 1.732 = 8.66m
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