A particle is thrown up inside a stationary lift of sufficient height. The time of flight is T. Now it is thrown again with same initial speed v 0 with respect to lift. At the time of second throw, lift is moving up with speed v 0 and uniform acceleration g upward (the acceleration due to gravity). The new time of flight is–
A
B
C
T
D
2 T
Text Solution
Verified by ExpertsThe correct answer is:
B
With respect to lift initial speed = v 0
acceleration = – 2g
displacement = 0
∴ S = ut + 
at 2
0 = v 0 T' + 
× 2g × T' 2
∴ T' = 
= 
× 
= 
T
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