Home Physics System of Particles Rotational Motion NTA Abhiyas Question A solid spherical ball of mass m is released…
Physics System of Particles Rotational Motion NTA Abhiyas Question MCQ (Single Correct)

A solid spherical ball of mass m is released from the topmost point of the shown semi-spherical shell. The track is sufficiently rough to enable pure rolling motion. The normal force between the ball and the shell at the lowest position is

A
B
C
D

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Text Solution

Verified by Experts
The correct answer is:
C

mg

From the law of conservation of mechanical energy,

Final energy = Translational kinetic energy + Rotational kinetic energy

Hence, Final energy

Hence, we finally obtain, .......(1)

and ..........(2)

Solving Eqs. (1) and (2), we get

N= mg

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