Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A uniform thin hemispherical shell is kept at rest and in equilibrium on an inclined plane of angle of inclination
= 30 ° as shown in the figure. If the surface of the inclined plane is sufficiently rough to prevent sliding then the angle a (in degree) made by the plane of hemisphere with inclined plane is

Text Solution
Verified by ExpertsThe correct answer is:
B
Step 1: Identify the angles involved. The angle of inclination of the plane is given as \( \theta = 30^{\circ} \). The angle \( a \) is the angle made by the plane of the hemisphere with the inclined plane.
Step 2: Since the hemispherical shell is in equilibrium and the surface is rough enough to prevent sliding, the angle \( a \) can be calculated as follows:
The force due to gravity acts vertically downward, splitting into two components: one parallel to the incline and another normal to it. Based on geometric considerations, we find that:
\( a + \theta = 90^{\circ} \)
Hence, \( a = 90^{\circ} - \theta = 90^{\circ} - 30^{\circ} = 60^{\circ} \).
Therefore, the angle \( a \) is \( 60^{\circ} \). Hence, option B is correct.
Step 2: Since the hemispherical shell is in equilibrium and the surface is rough enough to prevent sliding, the angle \( a \) can be calculated as follows:
The force due to gravity acts vertically downward, splitting into two components: one parallel to the incline and another normal to it. Based on geometric considerations, we find that:
\( a + \theta = 90^{\circ} \)
Hence, \( a = 90^{\circ} - \theta = 90^{\circ} - 30^{\circ} = 60^{\circ} \).
Therefore, the angle \( a \) is \( 60^{\circ} \). Hence, option B is correct.
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