Four solid spheres each of diameter
cm and mass 0.5kg are placed with their centres at the corners of a square of side 4 cm. The moment of inertia of the system about the diagonal of the square is N x 10 -4 kg m 2 , then N is
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CHECK THE SOLUTION.
9

m = 0.5 kg
a = 4 cm = 4 x 10~ 2 m



Substituting the values, we get,

Therefore, N = 9
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