A uniform rod AB of mass 2 kg and length 1 m is placed on a sharp support O, such that AO = a = 25 cm and OB = b = 75 cm. A spring of force constant 600 Nm -1 is attached to the end B, as shown. Initially, the spring is extended by 2 cm at equilibrium. As soon as the thread is burnt, find the normal force (in N) exerted by the support at O.
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CHECK THE SOLUTION.
8
about O is 
Spring force 
Torque, just after burning the string,
Acceleration of COM,
Now, total vertical force
12 + 20 - N = 2 x 12
N = 32-24 = 8N
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