An inverted bell, lying at the bottom of lake 47. 6 m deep, has 50 cm 3 of air trapped in it. The bell is brought to the surface of the lake, then the volume of the trapped air will become [atmospheric pressure = 70 cm of Hg and density of Hg = 13. 6 g cm -3 ]
Text Solution
Verified by ExpertsThe correct answer is:
B
300 cm 3
According to Boyle's law, pressure and volume are inversely proportional to each other i.e.
P 1 V 1 = P 2 V 2
[As P 2 =Po = 70 cm of Hg = 70 * 10 -2 * 13.6 * 1000 * 10]
V 2 = (1 + 5)50cm 3 = 300cm 3
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