Diagram shows the variation of internal energy (U) with the pressure (P) of 2. 0 mole gas in cyclic process abcda. The temperature of gas at c and d are 300 K and 500 K, respectively. Calculate the heat absorbed by the gas during the process.
Text Solution
Verified by ExpertsThe correct answer is:
B
Change in internal energy for cyclic process ( 
U) = 0
For process a 
b, (P - constant)
For process b 
c, (T - constant)
For process c 
d, (P - constant)
For process d 
a, (T - constant)
Net work,
dQ=dU+dW, first law of thermodynamics
dQ = 400 R ln 2
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