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Physics Thermodynamics NTA Abhiyas Question MCQ (Single Correct)

A pendulum clock (fitted with a small heavy bob that is connected with a metal rod) is 3 seconds fast each day at a temperature of 15 ° C and 2 seconds slow at a temperature of 30 ° C. Find the temperature (in ° C) at which it will show the correct time.

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The correct answer is:
CHECK THE SOLUTION.

(24.00)

Fractional loss of time per second =

Therefore (T 0 - 15) x (24hrs) = 3

and (30 - T 0 ) x (24hrs) = 2

on solving t 0 = 24 °C

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