In a special arrangement of Young's double-slit experiment, the distance between the slits d is twice the distance between the screen and the slits D, i.e d = 2D. For this setup, the value of D such that the first minima on the screen fall at a distance D from the centre O is found to be 
, where A is the wavelength of light used. What is the value of TV? [Take 
= 2.24]
Text Solution
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2.48
From diagram as provided in question, OP = x
CO = D
S 1 C = S 2 C = DT 1 P = TiO - OP = D - x
T 2 P = T 2 O + OP = D+x
Now, 
For fist minimum to occur,
Path difference
The first minimum falls at a distance D from the centre, i.e., x = D
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