Home Physics Ray Optics NTA Abhiyas Question A plano-convex lens has a radius of curvatur…
Physics Ray Optics NTA Abhiyas Question Subjective Type
Published on: September 12, 2026

A plano-convex lens has a radius of curvature of the curved surface equal to 30 cm and a refractive index equal to 1. 5, then what is the focal length (in cm) of the lens?

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
A
Step 1: Use the lens maker's formula for a plano-convex lens, which is given by:
$$ f = \frac{R}{2(n - 1)} $$
where:
- $f$ is the focal length of the lens
- $R$ is the radius of curvature of the curved surface
- $n$ is the refractive index of the lens material
Step 2: Substitute the given values into the formula:
Radius of curvature, $R = 30 \text{ cm}$
Refractive index, $n = 1.5$
$$ f = \frac{30}{2(1.5 - 1)} $$
Step 3: Calculate the values inside the brackets:
$$ n - 1 = 1.5 - 1 = 0.5 $$
Step 4: Now substitute this value:
$$ f = \frac{30}{2 \times 0.5} = \frac{30}{1} = 30 \text{ cm} $$
Therefore, the focal length of the lens is 30 cm.

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.