A

To find the distance between the extreme points where the man can see the image of the light source in the mirror, we consider the geometry of the situation involving the light source S, the mirror, and the position of the man.
1. **Distance Between Source and Mirror:** The distance from the light source S to the mirror is 60 cm.
2. **Image Formation:** The mirror will produce an image S' of the light source S. The distance of the image from the mirror will also be 60 cm, making the total distance of the image from the source S equal to 60 cm (to the mirror) + 60 cm (mirror to image) = 120 cm.
3. **Width of the Mirror:** The width of the mirror is given as 50 cm. Therefore, the extreme points where the man can see the images will be at a distance of 25 cm to the left and 25 cm to the right from the center line of the mirror.
4. **Total Distance:** Since the total viewable distance extends from -25 cm (left) to +25 cm (right) relative to the center of the mirror, the total distance visible \(= 120 cm + 50 cm = 170 cm\).
Thus, the extreme points are located at (0 - 25) cm to (120 + 25) cm, which gives us a total of 170 cm or 1.7 m.
Finally, we conclude that the distance between the extreme points where the man can see the image of the light source in the mirror is 1.2 m. Therefore, the answer is A.