Published by:
CGP EDU Academic Team
Published on: September 12, 2026
In the given figure a monkey of mass m is climbing up a rope hanging from the roof with acceleration a. The coefficient of static friction between the body of the monkey and the rope is µ. Find the direction and value of friction force on the monkey.

Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: Identify the forces acting on the monkey. The weight (mg) acts downward and static friction (f) acts upward if the monkey is accelerating upwards.
Step 2: Apply Newton's second law. The net force (F_net) acting on the monkey is given by:
F_{net} = m imes a = T - mg - f,
where T is the tension in the rope.
Step 3: The static friction can be expressed as:
f \leq \mu N,
where N is the normal force acting on the monkey, which is equal to the weight in this case, so N = mg.
Step 4: Thus, static friction can be maximized:
f_{max} = \mu mg.
Step 5: Since the monkey is accelerating upwards with acceleration 'a', the direction of the friction force is upwards to assist the monkey in climbing up.
Therefore, the direction of frictional force is upward, and its maximum value is \mu mg.
Step 2: Apply Newton's second law. The net force (F_net) acting on the monkey is given by:
F_{net} = m imes a = T - mg - f,
where T is the tension in the rope.
Step 3: The static friction can be expressed as:
f \leq \mu N,
where N is the normal force acting on the monkey, which is equal to the weight in this case, so N = mg.
Step 4: Thus, static friction can be maximized:
f_{max} = \mu mg.
Step 5: Since the monkey is accelerating upwards with acceleration 'a', the direction of the friction force is upwards to assist the monkey in climbing up.
Therefore, the direction of frictional force is upward, and its maximum value is \mu mg.
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