Published by:
CGP EDU Academic Team
Published on: September 12, 2026
What is the minimum value of force (in following two cases) required to pull a block of mass m on a horizontal surface having coefficient of friction µ? Also find the angle this force makes with the horizontal.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
μ mg
, tan –1 μ .
Sol.

N = mg – F sin θ
F cos θ = μ N = μ [mg – F sin θ ]
F = 
F is minimum when cos θ + μ sin θ is max
⇒
(cos θ + μ sin θ ) = 0
⇒ – sin θ + μ cos θ = 0
⇒ μ = tan θ
or θ = tan –1 μ
also, cos θ + μ sin θ
=
for θ = tan -1 μ
thus F min = 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The coefficient of friction $p_u$ and the angle of friction $\lambda$ are related as
A force of 98 N is required to just start moving a body of mass 100 kg over ice. The coefficient of…
A block weighs W is held against a vertical wall by applying a horizontal force F. The minimum valu…
The maximum static frictional force is
Pulling force making an angle θ to the horizontal is applied on a block of weight W placed on a hor…
In the figure shown, a block of weight 10 N resting on a horizontal surface. The coefficient of sta…