In the given figure the coefficient of friction between 4kg and 5 kg blocks is 0.2 and between 5 kg block and ground is 0.1. Choose the correct statements
Text Solution
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So, block ‘Q’ is moving due to force while block ‘P’ due to friction.
Friction direction on both P + Q blocks as shown.
First block ‘Q’ will move and P will move with ‘Q’ so by FBD taking ‘P’ and ‘Q’ as system
F – 9 = 0 
F = 9 N
When applied force is 4 N then FBD
4 kg block is moving due to friction and maximum friction force is 8 N.
So, acceleration = 
= 2 m/s 2 = a max .
Slipping will start when Q has +ve acceleration equal to maximum acceleration of P i.e. 2 m/s 2 .
F – 17 = 5 × 2 
F = 27 N.
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