In the figure shown, the coefficient of static friction between C and ground is 0.5, coefficient of static friction between A and B is 0.25, coefficient of static friction between B and C is zero. Find the minimum value of force ‘F’ (in newton), to cause sliding between A and B. Masses of A, B and C are respectively 2 kg, 4 kg and 5 kg.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(15)
Sol. The F.B.D. of A and B are
(force of friction)
For sliding to start between A and B, the frictional f = µ N = 
× 2 × 10 = 5 N = f max
Applying Newton’s second law to system of A + B
F = (m A + m B ) a = 6a ........
Applying Newton’s second law to A
f = m A a 
a max = 
= 
= 2.5 m/s 2 ........
from and F min = (m A + m B ) 2.5 m/s 2 = 6 × 2.5 = 15 N
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems