Home Physics Friction JEE (Advanced) / IIT-JEE Problems (Previous Years) A disc is kept on a smooth horizontal plane …
Physics Friction JEE (Advanced) / IIT-JEE Problems (Previous Years) MCQ (Single Correct)

A disc is kept on a smooth horizontal plane with its plane parallel to horizontal plane. A groove is made in the disc as shown in the figure. The coefficient of friction between mass m and surface of the groove is 2/5 and sin θ = 3/5. Find the acceleration of mass with respect to the frame of reference of the disc.

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The correct answer is:
CHECK THE SOLUTION.

(10 m/s 2 )

Sol.

Solving from the frame of disc

Let acceleration of the block relative to the disc is a then

25 m cos θ – μ N = m a ..........(i)

Now, there will be two normal as there are two contacts (i) Horizontal and (ii) Vertical

N H = 25 m×sin θ = 25 × m × = 15 m

N V = mg = 10 m

f = μ N H + μ N V = (15 m) + (10 m) = 10 m

from (i) we get a = = 10 m/sec 2

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