A block is moving on an inclined plane making an angle 45° with the horizontal and the coefficient of friction is µ. The force required to just push it up the inclined plane is 3 times the force required to just prevent it from sliding down. If we define k = 10 µ, then value of k is
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(5)

F 1 = 

F 2 = 
F 1 = 3F 2
1 + μ = 3 – 3 μ
4 μ = 2
μ = 
k = 10 μ
k = 5 Ans.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A disc is kept on a smooth horizontal plane with its plane parallel to horizontal plane. A groove i…
A small block of mass 0.1 kg lies on a fixed inclined plane PQ which makes an angle θ with the hori…
A block of mass m 1 = 1 kg and another mass m 2 = 2 kg, are placed together (see figure) on an incl…