The lower plate of a parallel plate capacitor is supported on a rigid rod. The upper plate is suspended from one end of a balance. The two plates are joined together by a thin wire and subsequently disconnected. The balance is then counterpoised. Now a voltage V = 5000 volt is applied between the plates. The distance between the plates is d = 5 mm and the area of each plate is A = 100 cm 2 . Then find out the additional mass placed to maintain balance. [All the elements other than plates are massless and nonconducting]

Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(
kg = 4.425 g)
The electric force between the plates will be balanced by the additional weight
hence mg =
=
, mg = 
m =
= 
m = 4.425 g
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems