Find the potential difference between the points A and B (V A – V B ) as shown in figure. (Initially all the capacitors are uncharged)

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( – 22 V)

assume (V A = 0), (V B = x)
From conservation of charge on plates of capacitor
4(x – 20) + (x – 10)6 + (x – 30)10 = 0
x = 22
V A – V B = 0 – 22 = – 22 V.
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